2x^2-25x-247=0

Solution for 2x^2-25x-247=0 equation:

2x^2-25x-247=0

a = 2; b = -25; c = -247;
Δ = b2-4ac
Δ = -252-4·2·(-247)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-51}{2*2}=\frac{-26}{4}
=-6+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+51}{2*2}=\frac{76}{4}
=19
$